(1/3)x^2+1/3x-2/3=0

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Solution for (1/3)x^2+1/3x-2/3=0 equation: 


x in (-oo:+oo)

(1/3)*x^2+(1/3)*x-(2/3) = 0

(1/3)*x^2+(1/3)*x-2/3 = 0

1/3*x^2+1/3*x-2/3 = 0

DELTA = (1/3)^2-(-2/3*1/3*4)

DELTA = 1

DELTA > 0

x = (1^(1/2)-1/3)/(1/3*2) or x = (-1^(1/2)-1/3)/(1/3*2)

x = 1 or x = -2

x in { -2, 1 }

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